Crocodile’s Desert Spada
Crocodile’s Desert Spada cuts through the palace lawn. It appears to be vaporization, and given Crocodile’s abilities, that does make sense. He used this move before on Luffy, but it was in the middle of the desert, and I wasn’t quite sure how to calculate it given the sand. Now that we have good old rock as our material, it’s easier.
Not a fan of how I had to scale Luffy here, but I didn’t see any other choice as this is the only view of the width of the destruction caused. At any rate, Luffy is 1.72 m tall. He measures at 369 pixels compared to 120 for width of vaporized rock.
120 / 369 = .325 * 1.72 = .559 m, width of vaporized rock.
Crocodile is 2.53 m tall. He measures 135 pixels here compared to the height of the merlon (Just found out that’s what it’s called. It’s been driving me crazy!) at 173.
173 / 135 = 1.282 * 2.53 = 3.244 m, height of merlon.
Alright, so I just want to clarify what the darker blue line is for real quick. It’s to establish where the ground is. We need to know that so we can get the depth of the hole made by Crocodile. The tricky perspective makes it so that we don’t know exactly where it is when measuring where the feat actually happened. Meanwhile, we can see where the ground is toward the middle of the lawn, so that’s what the blue line is for. The vertical lighter blue line is to establish where the sand is shooting up from, AKA the beginning of the attack. This is so we can get length.
The merlon measures 7 pixels tall compared to 19 for the depth of the hole and 62 for the length of it.
19 / 7 = 2.714 * 3.244 = 8.804 m, depth of hole.
62 / 7 = 8.857 * 3.244 = 28.732 m, length of hole.
Treating it as a rectangular prism, the volume of destroyed rock would be 141.403 m^3.
With rock being 2,700 kg/m^3, this would mean Crocodile vaporized 381,788.1 Kg of rock.
Vaporization point of rock is 2,470 C, and the temp change at standard temps would be 2,450 C. Specific heat of rock is 750 J/kg C.
381,788.1 * 750 * 2,450 = 701,535,633,750 J
Now we need to find latent heat of vaporization. Rock has a latent heat of vaporization of 4.8 KJ/g, or 4,800,000 J/Kg
381,788.1 * 4,800,000 = 1,832,582,880,000 J
1,832,582,880,000 + 701,535,633,750 = 2,534,118,513,750 J, or 605.669 Tons of TNT
I should note that in their final battle, Crocodile fires four of these at Luffy. Luffy punches through one of them, and it’s not exactly clear if he just lets the others hit him or if he dodges, but still, this is a testament to both, as Crocodile shows he’s capable of 4x this energy, and Luffy can break one of these with a single punch.
Crocodile Fractures the Palace Lawn
\
Crocodile gets angry and drys up the ground to the point where it fractures the entire palace lawn.
As previously established, Crocodile is 2.53 m tall. He’s 26 pixels here compared to the length of the lawn at 369.
369 / 26 = 14.192 * 2.53 = 35.906 m, length of lawn.
As previously established, the castle merlon is 3.244 m tall. What I’ve done here to capture the trapezoidal prism nature of the shape is measure half way for each required line measurement in this panel. This is because there’s no good full shot of the lawn that I can find. That said, as long as the castle was built in a uniform, symmetrical way, I think it’s a good way to get the sizes we need. I’ll just double the results that I get for the full dimensions.
The merlon is 7 pixels tall compared to the bottom dimension of the trapezoid at 285 and the upper dimension at 203.
285 / 7 = 40.714 * 3.244 = 132.076 * 2 = 264.152 m, bottom dimension.
203 / 7 = 29 * 3.244 = 94.076 * 2 = 188.152 m, top dimension.
Luffy is 1.72 m tall, as previously established. He measures 108 pixels here compared to 131 for the depth of the fissure.
131 / 108 = 1.213 * 1.72 = 2.086 m, depth of fissure.
With these dimensions and using a trapezoidal prism volume calculator, we find that the total fractured rock comes to 16,938.766 m^3.
Since this is fracturing, we’ll be using 8 J/cc to find energy.
16,938.766 m^3 = 16,938,766,000 cm^3
16,938,766,000 * 8 = 135,510,128,000 J, or 32.388 Tons of TNT.
Mind you, I haven’t accounted for him drying everything up and turning it to sand either. Not sure how I’d tackle that. I think that either way this shows that Crocodile has some multi-city block attacks up his sleeve in the Alabasta arc.
Pell Saves Alubarna
Pell flies up into the sky so that Crocodile’s bomb won’t destroy Alubarna. The blast diameter of the bomb is stated several times to be 5 Km. This would mean that in order for none of the city to be hit by the explosion, Pell would have had to fly at least the bomb’s radius, 2.5 Km. We also see that when he’s taking the bomb up into the sky, there’s 5 seconds left on the timer. He appears to fly straight up, and the whole thing is a very close call, with some minor damage to windows occurring. Wih all of the information we’re given, this is actually quite simple to calculate.
2.5 Km = 2,500 m.
2,500 / 5 = 500 m/s, or Mach 1.47
Luffy’s Gomu Gomu Storm
Luffy hits Crocodile with a barrage of punches that send him flying through several layers of rock and up into the sky. The result of shooting up through all of that rock is that a whole city block collapses!
… man Oda, you made this look impressive, but it sure was a pain figuring out sizes and such. Actually that can be said for most of the Alabasta arc feats.
Luffy is 1.72 m tall. He measures 9 pixels compared to the ceiling support at 44.
44 / 9 = 4.889 * 1.72 = 8.409 m, width of ceiling support.
Alright so for this one I’m going to use angular size to figure out the distance to the top. The panel is a little lopsided, but I feel that’s fine so long as there’s a good horizontal view. My assumption will be that the exit hole is the same size as the one in the tomb.
The ceiling support is 117 pixels wide compared to the big hole at 200.
200 / 117 = 1.709 * 8.409 = 14.37 m, diameter of hole.
The panel width is 573 pixels, and the human horizontal field of vision is 210 degrees.
573 / 210 = 2.729 pixels/degree.
16 / 2.729 = 5.863 degrees, size of exit hole.
Using the angular size calculator and inputting for distance, we find that the exit hole is 140.31 m away.
If we were to consider this a cylinder, that would make the volume of destroyed rock 22,755.797 m^3
I’m using explosive fragmentation for this one. Some debris is shot up, but there are no signs of burning or spall. 20 J/cc.
22,755.797 m^3 = 22,755,797,000 cm^3
22,755,797,000 * 20 = 455,115,940,000 J, or 108.775 Tons of TNT
Another multi-city block feat to cap off the Alabasta arc.
RESULTS
Crocodile’s Desert Spada – 605.669 Tons of TNT
Crocodile Fractures the Palace Lawn – 32.388 Tons of TNT
Pell Saves Alubarna – Mach 1.47
Luffy’s Gomu Gomu Storm – 108.775 Tons of TNT
Cable's Calculations 
Luffy Gomu Gomu storm also needs to be divided by the number of punches it took to create this feat as it was not done in a single shot/attack but hundreds of them if not more.
LikeLike