Orihime’s Shield Formation Speed
Mayuri sacrifices his own men by blowing them up right next to Orihime. As Ishida is warning her, you can see the light from the beginning of the explosion refelecting off of his face. One of the men who blew up was quite literally right next to Orihime. No signs of a shockwave, though, so that would make it 171 m/s as the minimum explosive speed.
Orihime is 1.57 m tall. She stands 149 pixels here compared to the distance away from the explosion at 55.
55 / 149 = .369 * 1.57 = .579 m, distance from explosion.
Ishida is 1.71 m tall. He measures 598 pixels compared to 722 for the shield height.
722 / 598 = 1.207 * 1.71 = 2.064 m, height of shield.
However, we have to assume that the shield expands not from top to bottom, but from the middle. Therefore, it would be half of that total, 1.032 m.
Ishida is also able to stand between the shield and Orihime, so that distance needs to be accounted for as well.
47 / 367 = .128 * 1.71 = .219 m, Ishida’s foot length.
.579 – .219 = .36 m, distance traveled by explosion before shield formation.
.36 / 171 = .0021 s, time frame.
1.032 / .0021 = 491.429 m/s, or Mach 1.45
Byakuya’s Hado 33
Byakuya’s Hado 33 creates a huge explosion. We can use the Taylor Formula to get the yield of the blast.
Byakuya is 1.80 m tall. He’s 79 pixels tall here compared to width of the roof at 294.
294 / 79 = 3.722 * 1.80 = 6.7 m, width of roof.
Width of the roof measures at 11 pixels compared to blast diameter at 445.
445 / 11 = 40.455 * 6.7 = 271.049 m, diameter of blast.
Now for Taylor’s Formula.
E = 8*pi*p*R^5 / [75(y-1)t^2]
Where p is density of the air, t is time after explosion has formed, R is radius of the explosion. y is specific heat ration (Will be using 1.4 here as is common)
For time, I’ll be using the speed of the explosion. There is no sign of a shockwave, so I’ll be using the minimum of 177 m/s.
135.525 m is the radius of the explosion.
135.525 / 177 = .766 s, time frame.
8 * 3.14 * 1.2 * 135.525^5 / [75(1.4 – 1).766^2] = 78,292,320,791.183 J, or 18.712 Tons of TNT.
Ichigo Breaks the Pole… and a Lot of Rock
In the process of destroying the Sokyoku pole, Ichigo punches a hole in Sokyoku hill with only his shikai.
Ichigo is 1.74 m tall. He’s 58 pixels here compared to 27 for the pole width.
27 / 58 = .466 * 1.74 = .811 m, width of pole.
The pole is 2 pixels compared to depth of the hole at 63.
62 / 2 = 31.5 * .811 = 25.547 m, depth of hole.
Depth of hole is 97 pixels compared to hole diameter at 51.
51 / 97 = .526 * 25.547 = 13.438 m, diameter of hole.
Treating the hole as a cylinder, the volume would be 3623.256 m^3
There is some spall from the feat, but there are also large chunks of debris to go along with it, and to make matters more confusing his reiatsu appears to be mixed in. I’m going to go with the mixture and call it cratering for now. That would give this an energy requirement of 87 J/cc.
3623.256 m^3 =3,623,256,000 cm^3
3,623,256,000 * 87 = 315,223,272,000 J, or 75.34 Tons of TNT.
Yoruichi’s Shunkou
Yoruichi unleashes Shunkou, which vaporizes some rock in the area. Oddly enough, I don’t think the energy release hits Soifon for some reason. That, or it had absolutely no effect on her. It’s a strangely laid out part of the chapter to be honest. lol
Lots to do here. First off, I’m going to use angular size to determine how far Yoruichi is away from our view to get the length. I measured the vertical length of the panel because the human vertical visual field is always below horizontal, so I can’t measure that in this particular panel. The other important factor is to ensure that the chunks of land that Soifon and Yoruichi are standing on are excluded form the calculation.
Human vertical field of vision is 150 degrees. The panel measures 603 pixels.
603 / 150 = 4.02 pixels/degree.
26 / 4.02 = 6.468 degrees, Yoruichi’s height.
We know that Yoruichi is 1.56 m tall. Using the angular size calculator, we can solve for distance and find that she is 13.804 m away.
As for the rest, Yoruichi measures at 26 pixels compared to 221 for width of destruction, 14 for the depth, 27 for the diameter Yoruichi is standing on, 50 for Soifon’s height, 170 for the length of the rock she’s standing on, and 132 for the width.
221 / 26 = 8.5 * 1.56 = 13.26 m, width of destruction.
14 / 26 = .539 * 1.56 = .841 m, depth.
If we treat this as a half oval cylinder, the volume comes to 120.902 m^3.
But hold up, we still need to account for that land that they’re both standing on. Let’s start with Yoruichi. Her platform is 27 pixels in diameter.
27 / 26 = 1.039 * 1.56 = 1.621 m, diameter.
As a cylinder, the volume would be 1.738 m^3
Soifon is 1.50 m tall. She measures at 50 pixels compared to the length at 170 and base at 132.
170 / 50 = 3.4 * 1.50 = 5.1 m, length.
132 / 50 = 2.64 * 1.50 = 3.96 m, base.
As a triangular prism, the volume would come to 7.83 m^3
120.902 – 1.738 – 7.83 =111.334 m^3, total volume of vaporized rock.
With rock being 2,700 kg/m^2, this would mean Yoruichi vaporized 300,601.8 Kg
Vaporization point of rock is 2,470 C, and the temp change at standard temps would be 2,450 C. Specific heat of rock is 750 J/kg C.
300,601.8 * 750 * 2,450 = 552,355,807,500 J
Now we need to find latent heat of vaporization. Rock has a latent heat of vaporization of 4.8 KJ/g, or 4,800,000 J/Kg
300,601.8 * 4,800,000 = 1,442,888,640,000 J
1,442,888,640,000 + 552,355,807,500 = 1,995,244,447,500 J, or 476.875 Tons of TNT
RESULTS
Orihime’s Shield Formation Speed – Mach 1.45
Byakuya’s Hado 33 – 18.712 Tons of TNT
Ichigo Pokes a Hole Through Sokyoku Hill – 75.34 Tons of TNT
Yoruichi’s Shunkou – 476.875 Tons of TNT
Cable's Calculations 
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