Yu Yu Hakusho – Yusuke vs Jin Feats

Some interesting feats involving wind in this fight. Thought it’d be fun to figure out how impressive it all is. We do know that Jin’s wind is capable of deflecting a 3.69 ton TNT Rei Gun, but how about some more direct calculations?

Jin’s Tornado Fist

The mini tornado around Jin’s fist spins with such great force that just grazing Yusuke sends him flying from the middle of the ring to the wall. I think from this we can get an idea of two things: The power behind Jin’s wind, and also speed.

First we need to figure out how far Yusuke flew to get some idea of how impressive this is.

Kuwabara is 1.80 m tall here and he measures at 42 Px. The ring is 477 Px.

477 / 42 = 11.357 * 1.8 = 20.443 m, the ring diameter.

Ring diameter is 42 Px and the distance from center ring to the wall is 78.

78 / 42 = 1.857 * 20.443 = 37.963 m, the distance Yusuke flew.

Now that we know distance, we need the angle from takeoff. First I’m going to use the width of Toguro’s shoulders as a reference (Bare with me)

Toguro is 2.42 m tall. He’s 352 px here, while his shoulder width is 134 px. I specifically picked him at 45% here, and you’ll see why in the next scaling.

134 / 352 = .381 * 2.42 = .922 m, 45% Toguro’s shoulder width

In this image, Toguro carries the ring on his shoulders. It’s generally accepted that he did this using 45%, because at 80% his aura kills fodder demons, and that didn’t happen until his fight with Yusuke. He’s also too buff in this image to be in his base form, which is relatively slim in comparison. Since 45% is the only other percentage he ever uses during this tournament, that’s what I’m going with here.

The right depth is 91 Px compared to Toguro’s shoulders at 60.

91 / 60 = 1.517 * .922 = 1.4 m, the height of the ring.

I know this is a lot of scaling that’s not Jin vs Yusuke, but these numbers will come in handy in later calculations. 😉

Now as we can see in the scan, Jin makes contact right at Yusuke’s chest level.

Yusuke is 1.64 m tall. He’s 404 Px here, with the distance between top of head and chest being 109 Px. Yusuke’s head is 71 Px.

71 / 404 = .176 * 1.64 = .287 m, the height of Yusuke’s head. We’ll need that for later.

109 / 404 = .27 * 1.64 = .443 m, distance between top of Yusuke’s head and his chest.

1.64 – .443 = 1.197 m, the height of Yusuke up to his chest.

1.197 + 1.4 = 2.597 m, Yusuke’s starting launch height from chest (Including ring thickness).

Next we need to figure out the height at which Yusuke landed, because he didn’t land on ground, but instead against the wall.

Yusuke’s head measures at 65 px compared to 110 for distance from top of wall to his chest.

110 / 65 = 1.692 * .287 = .486 m, distance from top of wall to Yusuke’s chest.

We found out the height of the DT arena wall is 2.723 m before, so…

2.732 – .486 = 2.246 m, Yusuke’s landing height.

2.597 – 2.246 = .351 m

Yusuke ended up .351 m lower than he started, which needs to be accounted for in the launch calculation.

Distance traveled of 37.963 m, so we have all we need. I’m going to give this a launch angle of 1 because we can very clearly see that Yusuke is shot straight at the wall and gets no vertical distance at all.

We can use this handy launch calculator to figure some things out. With this, and accounting for the drop off near the end, we find that Yusuke has a takeoff velocity of 83.508 m/s.

Now we need to find the acceleration from takeoff. We can do this by finding how much Jin’s mini tornado touched Yusuke’s chest to send him flying.

Yusuke’s head is 27 Px compared to the widest part of Jin’s mini tornado at 44. Reminder that we found Yusuke’s big ole’ anime head to be .287 m.

44 / 27 = 1.63 * .287 = .468 m, the greatest diameter of Jin’s mini tornado

We see in the scan from action lines that Yusuke is hit by what appears to be half a rotation of the mini tornado.

.468 m / 2 = .234, radius

That means the circumference of the mini tornado is 1.47. But since it’s half a rotation hitting Yusuke, let’s cut it in half. 1.47 / 2 = .735 m, the amount Jin’s tornado touched Yusuke for.

Now we can figure out the acceleration with a = v^2 / (2 d)

83.508^2 / (2*.735) = 4,743.936 m/s^2, the acceleration.

Now we can find the force with f = ma

For Yusuke’s mass, since he’s a bit smaller than the average Japanese man’s height, I’ll adjust the 68 kg weight with a cubed scaling law.

1.64 / 1.70 = .965^3 = .899 * 68 = 61.132, which we’ll round down to 61 Kg.

61 * 4,743.936 = 289,380.096 N 

Now we can find energy too. Work = force x distance.

289,380.096 * .735 = 212,694.371 J

While this on its own isn’t necessarily impressive, think about this much: This was only a piece of the mini tornado hitting Yusuke with half a rotation. I think that each second passing by would have high results for the tornado fist, but we’ll get to that next!

Finally, I want to get the speed he’s getting these tornadoes to spin at. We’re going back to good old Rotational Energy to figure out the angular velocity.

E =1/2 * Iw^2

E is rotational energy, I is angular velocity, and w is moment of inertia.

I = mr^2

So we need to find the mass of Jin’s tornado.

The smaller diameter of Jin’s tornado is 23 px. The length is 30 Px

23 / 27 = .852 * .287 = .245 m, smallest diameter of tornado.

30 / 27 = 1.111 * .287 = .319 m, length of the tornado.

Now we just need the thickness and we’re good to go.

30 / 331= .091 * .468 = .043 m, thickness of the tornado.

Treating it as a truncated cone, that would make the volume .033 m^3

But hold up, this tornado isn’t solid. That’s why I got the thickness earlier. If I subtract the thickness from both of my radius, I get a volume of .019 m^3

.033 – .019 = .014 m^3, true volume of the tornado.

Desnity of air is 1.225 kg/m^3

.014 * 1.225 = .017 kg, the weight of Jin’s tornado.

I’m going with the wider radius to figure out the moment of inertia. This is because it makes more sense for that part of the tornado to have hit Yusuke.

.468 / 2 = .234 m, radius.

I = mr^2

.017 * .234^2 = .000931 kg m^2, tornado moment of inertia.

E =1/2 * Iw^2 Solving for w

212,694.371= .5 * .000931 * w^2

w = 204,122 RPM or 3,402.033 Rotation/Second

For one rotation, the time frame would be .000294 s

Average radius is .178 (of upper and lower radius), so the total distance traveled for one rotation would be 1.12 m

1.12 / .000294 = 3,809.524 m/s or Mach 11.21

How about power generated? In one second…

3,809.524 * 212,694.371 = 810,264,310.989 J or 193.658 kg TNT per second

Double that to 387.316 kg TNT per second for the double tornado fist

Tornado Fist Part 2

This one will be a lot more simple thankfully. Jin’s Tornado Fist destroys the wall, sends some people flying, and even makes a crater in the ground all at once.

As we’ve established before, the DT wall is 2.723 m tall. The wall is 210 Px, while the widest destruction is 622, the smallest destruction is 193, and the crater is 199 Px.

622 / 210 = 2.962 * 2.723 = 8.066 m, the widest destruction of the wall.

193 / 210 = .919 * 2.723 = 2.502 m, the smallest width of destruction.

199 / 210 = .948 * 2.723 = 2.581 m, diameter of the crater.

We’ve also established that the DT wall is .803 m thick from the blog linked above.

Since the destruction is similar to a trapezoid, we can find the volume as a trapezoidal prism. It comes out to 11.554 m^3

11.554 = 11,554,000 cm^3

We’ll use the 15 j/cc amount for violent fragmentation.

11,554,000 * 15 = 173,310,000 J, or 41.422 kg TNT

Not so fast, there’s still the crater that Jin made, and I have a number for cratering too.

If we assume the crater made by Jin is a perfect half sphere, the volume would come to 4.5 m^3 or 4,500,000 cm^3

Now according to my findings making a crater would be 87 J/cc.

4,500,000 * 87 = 391,500,000 J, or 93.571 kg TNT

Combined totals come to 564,810,000 J, or 134.993 kg TNT

 

TOTALS

Tornado Fist Energy Generated Per Second: 193.658 kg TNT

Double Tornado Fist Energy Generated Per Second:  387.316 kg TNT

Tornado Fist Angular Velocity:  3,809.524 m/s or Mach 11.21

Tornado Fist vs The Wall: 134.993 kg TNT